x^2-5/2x+1=0

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Solution for x^2-5/2x+1=0 equation: 


x in (-oo:+oo)

x^2-((5/2)*x)+1 = 0

x^2+(-5/2)*x+1 = 0

x^2-5/2*x+1 = 0

DELTA = (-5/2)^2-(1*1*4)

DELTA = 9/4

DELTA > 0

x = ((9/4)^(1/2)+5/2)/(1*2) or x = (5/2-(9/4)^(1/2))/(1*2)

x = 2 or x = 1/2

x in { 1/2, 2 }

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